(9x^2-42x+49)=0

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Solution for (9x^2-42x+49)=0 equation: 



(9x^2-42x+49)=0

We get rid of parentheses

9x^2-42x+49=0

a = 9; b = -42; c = +49;
Δ = b2-4ac
Δ = -422-4·9·49
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{42}{18}=2+1/3$

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